Hint

In fig (A), (3 × 3) + (6 × 5) = 39
In fig (B), (4× 4) + (5 × 7) = 51
∴ In fig (C), missing number
= (3 × 4) + (5 × 5) = 37

Hint

The arrangement is as follows :
In fig. (A), (3² + 6²) – (2² + 4²) = (9 + 36) – (4 + 16)
= 45 – 20 = 25
In fig. (B), (7² + 11²) – (8² + 6²) = (49 + 121) – (64 + 36)
= 170 – 100 = 70
In fig. (C), let the missing number be x.
Then, (1² + 4²) – (5² + x²) = –12
or 17 + 12 = (52 + x2) or x² = 29 – 25 = 4
or x = 2

Hint

In fig. (A), (6 × 3) + (5 × 15) = 18 + 75 = 93.
In fig. (C), (4 × 8) + (18 × 1) = 32 + 18 = 50.
∴ In fig. (B), missing number
= (9 × 6) + (7 × 5) = 54 + 35 = 89.

Hint

In fig. (A), (16 – 6)² + (5 – 2)² = 10² + 3² = 109.
In fig. (B), (22 – 15)² + (21 – 19)²
= 7² + 2² = 53.
∴ In fig. (C), missing number
= (17 – 13)² + (51 – 48)² = 4² + 3² = 25.

Hint

The lower number is obtained by adding the square of the upper two numbers. Thus,
In fig. (A), 2² + 4² = 20
In fig. (B), 3² + 9² = 90
∴ In fig. (C), missing number = 1² + 5² = 26

Hint

The above three numbers are multiples of the number at the bottom.
Clearly, 36, 18 and 27 are all multiples of 9.
So, the missing number is 9.

Hint

Hint

This way, the sum of the numbers in the same shape total 33.

Hint

We have (56 + 15) – (22 + 8)
= 41, (46 + 9) – (10 + 6) = 39
So, missing number = (34 + 11) – (14 + 6) = 25.

Hint

We have : 4 × 2 – 1 = 7, 7 × 2 + 1 = 15,
15 × 2 – 1 = 29 × 2 + 1 = 59,
59 × 2 – 1 = 117, 117 × 2 + 1 = 235.
So missing number = 235 × 2 – 1 = 469.

Hint

We have : 3 × 5 + 1 = 16 ,
16 × 5 + 1 = 81, 81 × 5 + 1 + 1 = 406.
So , missing number = 406
406 × 5 + 1 = 2031.

Hint

The arrangement is :5 + 3 = 8, 8 + 4 = 12, 12 + 1 = 13.
So, the missing number is 12.

Hint

The above three numbers are multiples of the number at the bottom. Clearly 36, 18 and 27 are all multiples of 9. So, the missing number is 9.

Hint

The sum of the two numbers in the upper part is 7 times the number in the lower part.
So, missing number = (89 + 16) + 7 = 15.

Hint

We have : (3 × 4 × 2 × 5) ÷ 10 = 12 ;
(6 × 2 × 3 × 5) ÷ 10 = 18.
So, missing number = (2 × 2 × 9 × 5) ÷ 10 = 18

Hint

We have : (5 x 3) + (6 x 8) = 63, (2 x 7) + (3 x 9) = 41
So, missing number = (6 x 7) + (8 x 5)
= (42 + 40) = 82.

Hint

We have : + + + = 26 ;
+ + + = 21
So, missing number
= + + +
= (5 + 12 + 6 + 8) = 31

Hint

We have (15 – 5) (2 + 6) = 80, (9 – 4) (7 + 6) = 65
So, missing number = (13 – 11 ) x (16 + 8) = 48.

Hint

The number inside the circle is obtained by multiplying the sum of the upper number, the lower number and the number corresponding to the position of the letter in the english alphabet, by the number on the right and then subtracting the number on the left from the product.
Thus we have (2 + C + 5) x 3 – 4 = (2 + 3 + 5) x 3 – 4 = 26 ; (4 + H + 4) x 5 – 10 = (4 + 8 + 4) x 5 – 10 = 70.
Let the missing number be x.
Then (8 + J + 6) × x – 6 = 90
⇒ (8 + 10 + 6) × x = 96 ⇒ x = 4.

Hint

The letter in the second column is three steps behind that in the first column, and the letter in the third column is four steps behind that in the second column. So, the missing letter in the first row will be three steps behind Z, which is W. The missing letter in the second row will be four steps behind O, which is K. The missing letter in the third row will be three steps ahead of G, which is J.

Hint

The letters in the first row follow the sequence + 5, + 7.
The letters in the second row follow the sequence + 6, + 8.
In the third row, the first letter G moves 7 steps forward to give the second letter N. Clearly, the missing letter will be 9 steps ahead of N i.e. W.

Hint

Putting A = 1, B = 2, C = 3, ……., M = 13, ….., X = 24,
Y = 25, Z = 26, we have :
In the first column, F – A = 6 – 1 = 5 = E.
In the second column, W – J = 23 – 10 = 13 = M.
\ In the third column, missing letter
= O – K = 15 – 11 = 4 = D.

Hint

Consecutive letters occupy alternate positions in each row.

Hint

The letters in the first row form a series C, D, E (a series of consecutive letters). The letters in the second row form a series I, K, M (a series of alternate letters). Similarly, the letters in the third row will form the series D, G, J (a series in which each letter is three steps ahead of the previous one). So, the missing letter is G. Also, the number in the second column is equal to the product of the numbers in the first and third columns.
So, missing number is (4 × 7) i.e. 28.
Thus, the answer is 28G.

Hint

In each row, out of the letters A, B and C, each of these must appear one. Also, in each column. The product of first and third numbers is equal to the second numbers so, the missing number will be (2 x 4) i.e, 8 and the missing letter will be C. Thus, the answer is 8C.

Hint

Hint

16 = 5 × 3 + 1, 51 = 16 × 3 + 3, 158 = 51 × 3 + 5
∴ Next term = 158 × 3 + 7 = 481

Hint

Second term is greater than first term by 5, while the third term is less than the second term by 3. The same order is repeated.

Hint

There are two alternate series
Series I: 6.25, 12.25, 20.25, 30.25 (sequence is +6, +8, +10)
Series II: 9, 16, 25, 36, (sequence is +7, +9, +11)

Hint

The given series consists of 2 series
(i) 2, 4, 6, 8 ………….
(ii) 2, 4, 8 ………….
Series (i) → 2× 1, 2 × 2, 2 × 3 , 2 × 4 …….
Series (ii) → 2, 2× 2, 4 × 2, 8 × 2 = 16 …….